Sediments — Sieve It, Pour It, Read It
Sieve a beach and grade it on the Wentworth scale. Make an underwater avalanche in a box, then time the real one that broke the Atlantic cables in 1929. Measure how mud steals light, heat and breath from living things. Finally, read 200 000 years of history from one deep-sea core.
Depth column, block 34: "Sediments is an important area of Oceanographic study and should be learnt with the view to apply the content to practicals and project work." Investigations column: "Refer to the turbidity current that severed the telephone line between London and New York · Use Secchi disk to record the turbidity or transparency of the water column · Refer to the impact sediments have on ecosystems in oceans (such as temperature change, clogging of animals' gaseous exchange organs, effects on plants' capacity to photosynthesise) · Create a turbidity current model with sediment · Obtain a sediment sample and analyse the grain size."
Grain size is Investigation 1. The turbidity-current model and the 1929 cable breaks are Investigation 2. The Secchi disk is Investigation 3. Sediment's effects on living things — heat, gills and photosynthesis — are Investigation 4. Investigation 5 reads a sediment core (CAPS key concept 13) and answers the booklet's own questions.
What you need
- 🌊 shore Two cupfuls of sediment: one of beach sand, and one from a river mouth or estuary bank. Take them from a public beach, outside any nature reserve or marine protected area.
- 🟢 kitchen A kitchen scale that reads to 1 g, a baking tray, and four sieves of different mesh: a colander, an ordinary kitchen sieve, a tea strainer and a fine flour or icing-sugar sieve. A ruler and some bowls.
- 🟢 kitchen A clear plastic storage box or glass dish at least 30 cm long, a plastic chopping board to lean inside it as a ramp, a jug, cups, a tablespoon, food colouring, and some garden soil (not potting mix)
- 🟢 kitchen A clear 2-litre bottle with its top cut off, a white plastic lid, a black permanent marker, a coin, and a stopwatch or phone
- 🟢 kitchen Two identical glass jars, a kitchen thermometer, a desk lamp (or a sunny windowsill), a funnel and paper coffee filters, bicarbonate of soda, dishwashing liquid and a few spinach leaves
- 🟡 pharmacy A 10 or 20 mL plastic syringe with no needle, and a hand lens
- 🟢 kitchen Graph paper, a calculator and coloured pencils
Every investigation has a supplied results panel: two sieved Algoa Bay samples, three timed turbidity currents in a box, the 1929 cable breaks, a full Secchi-tube series, three tests of what mud does to life, and a described deep-sea core. Use them and answer exactly the same questions.
Aim
To sort two sediment samples into Wentworth size classes, compare how well each is sorted, and see how size and shape control how fast a grain settles.
Method
- Measure each sieve. Lay a ruler across the mesh and use the hand lens to count the holes in 1 cm. The opening is roughly 10 mm ÷ the number of holes (a little less, because of the wire). Most kitchens give about 4 mm (colander), 1 mm (kitchen sieve), 0.5 mm (tea strainer) and 0.25 mm (flour sieve). Write your own sizes in Table 1.1.
- Dry the sample completely — spread it thinly on a tray in full sun for a day, or in an oven at about 100 °C for an hour with an adult. Crumble any lumps with your fingers without crushing the grains.
- Weigh out 500 g of the dry sample. This is the initial mass.
- Shake the whole sample in the colander over a bowl for one minute. Weigh what stays in the colander. Pour what fell through into the kitchen sieve and repeat, then the tea strainer, then the flour sieve. Weigh what passes the finest sieve — this is the pan.
- Repeat with the second sample.
- The settling race. Fill the 2-litre bottle with water and mark a line 25 cm below the surface. Time each of these falling from the surface to the line: a small rounded pebble; a flat piece of shell of about the same mass; a pinch of grains from each sieve. Then drop a pinch of the pan into the water and note how long the water stays cloudy.
Supplied results — two Algoa Bay samples, and a settling race
| Sieve (measured opening) | Size class caught | A — Kings Beach, upper beach (g) | B — Swartkops river-mouth sandbank (g) |
|---|---|---|---|
| colander (4 mm) | pebbles and shell bits, > 4 mm | 3 | 61 |
| kitchen sieve (1 mm) | granules and very coarse sand, 1–4 mm | 22 | 88 |
| tea strainer (0.5 mm) | coarse sand, 0.5–1 mm | 96 | 102 |
| flour sieve (0.25 mm) | medium sand, 0.25–0.5 mm | 291 | 97 |
| the pan | fine sand and finer, < 0.25 mm | 84 | 147 |
| Particle | Time (s) | What was seen |
|---|---|---|
| rounded pebble, 6 g | 0.4 | fell straight down |
| flat piece of shell, 6 g | 1.4 | rocked from side to side like a falling leaf |
| granules (2–4 mm) | 1.1 | fell straight |
| coarse sand (0.5–1 mm) | 2.6 | fell as a loose cloud of grains |
| medium sand (0.25–0.5 mm) | 5.8 | a slower, spreading cloud |
| a pinch of the pan | 15–40 for the sand | the water turned milky; the milkiness sank below the line in about 2 hours, the water was still faintly cloudy next day, and clear after 3 days, with a thin skin of mud on top of the sand |
Results
| Sieve | Your opening (mm) | Mass A (g) | % of A | Mass B (g) | % of B |
|---|---|---|---|---|---|
| colander | |||||
| kitchen sieve | |||||
| tea strainer | |||||
| flour sieve | |||||
| the pan | — | ||||
| total | — |
Analysis
- Why must the sample be completely dry before it is sieved? 2
- Complete Table 1.1 for both samples — yours or the supplied ones — showing one calculation in full. 6
- Neither total reaches 100 %. Calculate how much mass was lost from each sample, and give two reasons for the loss. 3
- Draw a bar graph of the percentage in each size class for both samples on one set of axes. 5
- Name the size class that holds the most sediment in each sample, using the Wentworth names. 2
- Which sample is better sorted? Use figures from your table. 2
- Your booklet says that sediment settling in turbulent water "tends to contain very mixed material". Yet Sample A comes from a wave-beaten beach and is the better sorted. Suggest how both can be true. 3
- The kitchen sieves split the sand at 1, 0.5 and 0.25 mm — exactly the Wentworth boundaries. (a) What opening would a fifth sieve need to split the pan into fine and very fine sand? (b) Why can no kitchen sieve separate silt from clay, and how did the settling race separate them instead? 3
- Compare the rounded pebble and the flat shell in Data set 1.2. What does this show about particle shape? Link your answer to the booklet's clay particles that "float" down "like a feather". 3
- Describe the pattern between grain size and settling time, and use it to explain why CAPS says fine sediments are deposited "in places such as quiet bays or estuaries" while coarse sediments stay "close to their source in turbulent waters". 3
- Answer the booklet's question 6 as numbered steps: "Describe the method of determining the sediment grain size in a sample against the Wentworth scale." 5
- Write the CAPS particle-size classification in decreasing order — all eleven names — with the two size limits CAPS gives. 4
Aim
To make a turbidity current, find out what makes it faster, read the layer it leaves behind — and then measure the speed of the real 1929 Grand Banks current from the times the cables broke.
Method
- Lean the chopping board inside one end of the box as a ramp, from the rim down to the floor. Prop its top edge about 5 cm high for a low ramp. With a marker, draw lines across the floor every 5 cm, measured from the foot of the ramp.
- Fill the box with tap water about 10 cm deep. Wait two minutes for it to go still.
- The control. Stir three drops of food colouring into a cup (250 mL) of water. Pour it slowly down the back of a spoon at the top of the ramp. Watch for 60 seconds.
- Change the water. Run a: stir 3 tablespoons of garden soil and three drops of colouring into 250 mL of water, stir hard, and pour it at once, the same way. Start the timer as you pour, and record the time the front (the "head") of the current passes each line.
- Run b: prop the ramp about 10 cm high (a steep ramp) and repeat with 3 tablespoons. Run c: back to the low ramp, with 6 tablespoons of soil.
- Leave the last run undisturbed overnight. Next day, look at the deposit from the side and from above. Measure its thickness at the foot of the ramp and along the floor, then cut down through it with a spoon at 10 cm and describe the layers from the bottom up.
Supplied results — three currents, a control and a deposit
| Run | 5 cm | 10 cm | 15 cm | 20 cm | 25 cm |
|---|---|---|---|---|---|
| a — low ramp, 3 tbsp | 3.4 | 6.0 | 8.9 | 12.2 | 16.0 |
| b — steep ramp, 3 tbsp | 2.2 | 4.1 | 6.2 | 8.6 | 11.3 |
| c — low ramp, 6 tbsp | 2.6 | 4.6 | 6.9 | 9.5 | 12.4 |
The control. The coloured water spread out as a faint cloud near where it was poured and mixed through the water from top to bottom. After 60 s the colour had reached only about 6 cm along the floor, and there was no sharp front.
The runs. Each slurry slid down the ramp as a dark, rolling tongue that hugged the floor, with a rounded head and clear water above it. Above the current the water stayed almost clear for the first few seconds.
Data set 2.2 — the deposit from run c, next day. The water above was clear except for a faint haze. The deposit was 7 mm thick at the foot of the ramp, 4 mm at 10 cm and 1.5 mm at 25 cm. Cut at 10 cm, from the bottom up: 2 mm of gritty coarse sand, 1.5 mm of fine sand, and 0.5 mm of smooth brown mud on top. At 25 cm there were no coarse grains at all — only fine sand under a skin of mud.
| Cable break | Distance down the flow path (km) | Time after the earthquake |
|---|---|---|
| six cables near the epicentre | 0–60 | at the moment of the earthquake |
| 1 | 65 | 0 h 59 min |
| 2 | 185 | 3 h 03 min |
| 3 | 270 | 4 h 54 min |
| 4 | 360 | 7 h 36 min |
| 5 | 430 | 10 h 18 min |
| 6 | 500 | 13 h 17 min |
Results
Analysis
- Calculate the average speed of the front between the 5 cm and 25 cm lines for runs a, b and c, in cm/s. 3
- Name the independent variable in the comparison of runs a and b, and in the comparison of runs a and c. Give one variable that was controlled. 3
- State what each comparison shows. 2
- The coloured water in the control did not make a current. What does that prove about what drives a turbidity current? 2
- Use the data for run a to show that the front slowed down as it travelled, and give a reason. 3
- Draw a labelled side view of the deposit (Data set 2.2 or your own). Name this kind of layering, and explain why the coarse grains are at the bottom. 5
- Say what each part of the model represents on a real continental margin: the ramp; the slurry; the flat floor of the box; the thick wedge of deposit at the foot of the ramp. 4
- Plot the distance of each sequential cable break against the time after the earthquake, starting from (0, 0), and draw a smooth curve. 4
- Calculate the speed of the current (km/h) between each pair of breaks, and its average speed over the whole 500 km. 4
- Describe how the current's speed changed, and suggest two reasons. 3
- Six cables near the epicentre broke at the very moment of the earthquake. Why can they not be used to measure the current's speed? 2
- Convert the fastest speed in your model and the fastest speed of the 1929 current into m/s. About how many times faster was the real one? Give one reason the model cannot simply be scaled up. 4
- CAPS calls this "the turbidity current that severed the telephone line between London and New York". Correct two things in that description. 2
Aim
To measure how the amount of suspended sediment changes the depth at which a Secchi disk disappears — the one thing the field readings in Practical 1 could not separate from plankton and weather.
Method
- Make a mini Secchi disk: cut a 5 cm circle from a white plastic lid, colour two opposite quarters black with the marker, and tape it face-up onto a coin so it sinks flat. Stand it on the bottom of the empty cut-off bottle.
- Sieve some garden soil through the flour sieve (or use the pan from Investigation 1). In a jug, stir 16 g of it into 2 litres of water. This is 8 g/L.
- Stir hard, then pour the muddy water slowly into the bottle while looking straight down at the disk from above, in shade. Stop the moment the disk disappears. Measure the depth of water above the disk with a ruler held against the outside. Pour it back, stir and repeat twice more.
- Halve the concentration: keep 1 litre of the 8 g/L water, pour away the rest, and add 1 litre of clean water — this is 4 g/L. Repeat step 3. Keep halving: 2 g/L, 1 g/L, 0.5 g/L.
Supplied results — a Secchi-tube series, and Algoa Bay after a flood
| Concentration (g/L) | Trial 1 | Trial 2 | Trial 3 |
|---|---|---|---|
| 8 | 3.0 | 3.5 | 3.0 |
| 4 | 6.5 | 6.0 | 6.5 |
| 2 | 13 | 12 | 12 |
| 1 | 24 | 26 | 25 |
| 0.5 | still visible with the bottle full (about 30 cm) — it never disappeared | ||
Data set 3.2 — near the Swartkops river mouth. A Secchi disk lowered from a boat disappeared at 5.5 m during a calm week, and at 1.2 m two days after a flood brought brown water out of the river. A reef nearby carries red seaweeds at a depth of 9 m.
A rule of thumb (Poole and Atkins, 1929, still used today): the bottom of the euphotic zone — the depth where about 1 % of surface light remains, and below which plants cannot make more food than they use — lies at about 2.7 × the Secchi depth.
Results
| Concentration (g/L) | 8 | 4 | 2 | 1 | 0.5 |
|---|---|---|---|---|---|
| Mean depth (cm) |
Analysis
- Calculate the mean disappearance depth for each concentration. 3
- Plot the mean depth against the concentration and draw a smooth curve. 4
- Describe the relationship. Multiply each mean depth by its concentration and say what your answers show. 3
- Use the relationship to predict the disappearance depth at 0.5 g/L, and explain why the disk never disappeared. 2
- Why was each depth measured three times, and why always in shade and by the same person? 2
- Name two things other than sediment that make real seawater less clear, and explain why this kitchen test measures the effect of sediment alone. 3
- Use the rule of thumb to calculate the depth of the euphotic zone near the Swartkops mouth in the calm week and after the flood. Can the red seaweeds at 9 m photosynthesise enough in each case? 4
- A developer says, "Our dredging only makes the water muddy — it doesn't poison anything." Use your results to argue that muddy water alone can kill a seaweed bed. 3
Aim
To test the three harms CAPS names: whether suspended sediment warms water, clogs a filter the way it clogs a gill, and slows photosynthesis.
Method
Test A — heat.
- Pour 500 mL of water from the same jug into each jar. Stir 2 teaspoons of fine sieved soil into one of them.
- Stand both jars side by side 20 cm from the lamp, or in full sun. Stir each gently and read its temperature every 5 minutes for 30 minutes.
Test B — a model gill.
- Line the funnel with a coffee filter. Pour 200 mL of clean water through it and time how long it takes to drain. Pour three more lots through the same filter, timing each.
- Repeat with a new filter and 200 mL lots of the 4 g/L muddy water from Investigation 3, stirred each time.
Test C — photosynthesis behind muddy water.
- Dissolve ¼ teaspoon of bicarbonate of soda in 300 mL of water with one drop of dishwashing liquid. The bicarbonate supplies carbon dioxide.
- Punch 40 discs from spinach leaves with a drinking straw. Put 10 at a time into the syringe with some bicarbonate solution, cover the tip with your finger, and pull the plunger back hard a few times. This draws the air out of the leaf, and the discs sink.
- Put 10 sunk discs into each of three glasses of bicarbonate solution. Stand each glass so the lamp shines on it through a "screen" jar: one of clear water, one of 2 g/L muddy water, one of 8 g/L muddy water.
- Control: put 10 sunk discs into a glass of plain water with no bicarbonate, behind a clear-water screen.
- Count the discs floating in each glass every 2 minutes for 20 minutes.
Supplied results — heat, a clogged filter and floating leaf discs
| Time (min) | 0 | 5 | 10 | 15 | 20 | 25 | 30 |
|---|---|---|---|---|---|---|---|
| clear water | 20.0 | 20.6 | 21.1 | 21.5 | 21.9 | 22.3 | 22.6 |
| muddy water | 20.0 | 21.0 | 22.0 | 22.9 | 23.7 | 24.4 | 25.0 |
| Pour | 1 | 2 | 3 | 4 |
|---|---|---|---|---|
| clean water | 14 | 14 | 15 | 14 |
| muddy water (4 g/L) | 17 | 26 | 41 | 72 |
After the fourth muddy pour, the filter was coated inside with a smooth brown film and was still dripping.
| Time (min) | 0 | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 | 18 | 20 |
|---|---|---|---|---|---|---|---|---|---|---|---|
| clear screen | 0 | 0 | 1 | 3 | 5 | 7 | 9 | 10 | 10 | 10 | 10 |
| 2 g/L screen | 0 | 0 | 0 | 1 | 2 | 3 | 5 | 6 | 7 | 8 | 9 |
| 8 g/L screen | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 2 | 2 | 3 |
| control — no bicarbonate | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
Tiny bubbles could be seen on the discs under the hand lens before they rose.
Analysis
- Calculate the temperature rise in each jar over the 30 minutes, and each jar's rate of warming in °C per 10 minutes. 3
- Explain why the muddy water warmed faster. 2
- Suggest two ways in which warmer surface water could harm the animals living in it. 2
- Describe the trend in the drain times for each filter, and explain the difference. 3
- The filter stands for a fish's gills or a mussel's filter. Explain how suspended sediment harms (a) a fish and (b) a mussel. Use the term gaseous exchange. 4
- Give one way in which a coffee filter is unlike a real gill. 1
- Explain why a leaf disc floats as it photosynthesises, and what the control discs prove. 3
- Draw a line graph of the number of discs floating against time for the three screens, on one set of axes. 5
- From your graph, read the time for half the discs (5) to float behind each screen. What does this show about sediment and photosynthesis? 3
- Name the independent variable in Test C, and two variables that were controlled. 3
- Suppose dredging in a harbour stirs up seabed mud for several weeks beside a rocky reef. Write a paragraph predicting the effects on the reef, using the results of all three tests and Investigation 3. 5
Aim
To read the history written in a sediment core — its origins, its ages, its climate and its one sudden event — and to answer the booklet's questions on sampling, acoustic sounding and resources.
A piston core, 240 cm long, from the abyssal plain of the Cape Basin off the West Coast, in 4 500 m of water. Layers from the top of the core (the present-day seabed) downwards:
Your core
Analysis
- Draw the core to scale as a labelled column (1 cm on your page = 10 cm of core), with a depth scale every 50 cm. Shade each layer differently and show the grading in layer 4. 6
- The core holds an example of all four origin categories. Name each category and the evidence for it in the core. 4
- Which layer was laid down by a turbidity current? Give three pieces of evidence. 4
- Estimate the age of the sediment at the bottom of the core. Show why one layer must be left out of the calculation. 4
- What does layer 5 tell you about the climate when it formed, and roughly how many years ago was that? 3
- The booklet calls a dredge sample "haphazard". Explain why a dredge sample from this same spot would have been almost useless for Q45–Q49, and why the booklet says a corer is best. 3
- The booklet's examinable definition of hydrogenous is "of or containing hydrogen". (a) Write it down — it is the one to give in a definitions question. (b) Explain why it misleads you about a manganese nodule, and give a better description of hydrogenous sediment. 3
- The booklet says acoustic sounding uses "a radar scanner". Correct this, and explain how acoustic profiling identifies the layers in sediment without collecting a sample. 3
- Answer the booklet's question 8: describe the range of resources found in marine sediments, giving a place for each. Include the South African and African examples CAPS names. 6
CAPS says sediments should be learnt "with the view to apply the content to practicals and project work". Investigation 1 is a ready-made Expo project (Topic 05): sieve samples every 20 m from the low-tide line to the dunes on one beach, or from a river mouth out along the beach, and test a hypothesis such as "sand gets finer and better sorted towards the dunes, because only wind can carry it there". Keep every sample the same mass, dried the same way, sieved for the same time.
Memo — worked answers and mark allocation (does not print)
Total: 176 marks — Investigation 1: 41 · Investigation 2: 41 · Investigation 3: 24 · Investigation 4: 34 · Investigation 5: 36.
Investigation 1 — sieve a beach
- Q1 (2): Damp grains stick together in clumps (1), so fine grains would be held back on the coarser sieves and the fractions would be wrong — and the water itself would add mass (1).
- Q2 (6): One calculation shown, e.g. 291 ÷ 500 × 100 = 58.2 % (1). A: 0.6 · 4.4 · 19.2 · 58.2 · 16.8 % (2). B: 12.2 · 17.6 · 20.4 · 19.4 · 29.4 % (2). Totals: A 496 g = 99.2 %; B 495 g = 99.0 % (1). Accept the learner's own correctly calculated results.
- Q3 (3): A lost 4 g (0.8 %) and B lost 5 g (1.0 %) (1). Any two: dust blew away while shaking; grains stuck in the mesh; grains spilled between sieves; the scale reads only to 1 g, so each reading is rounded (2).
- Q4 (5): Bars for all five classes for both samples, side by side (1); size classes in order along the x-axis, labelled (1); y-axis "% of initial mass" with an even scale (1); accurate bars (1); key and title (1).
- Q5 (2): A — medium sand, 0.25–0.5 mm (1). B — fine sand and finer, the pan, below 0.25 mm (1).
- Q6 (2): A is better sorted: 58.2 % in one class and over 75 % in two neighbouring classes (1). B is spread over all five classes, none above 30 % (1).
- Q7 (3): The booklet is describing water that drops its load all at once — a flood or a turbidity current — so every size settles together, unsorted (1). A beach is worked by waves at much the same energy every day for years: the backwash carries the fine grains away and the waves cannot carry the big pieces up the beach, so sand of one size is left (1). Sorting needs time and a steady energy level; a river mouth has sudden changes — floods, tides, calm spells — so it stays mixed (1).
- Q8 (3): (a) 0.125 mm (⅛ mm) (1). (b) Silt (below 0.0625 mm) and clay (below 0.0039 mm) are far finer than any kitchen mesh, and the grains clump together (1). They separate by settling speed instead: in still water silt settles in minutes to hours, clay over days, so they form separate layers (1).
- Q9 (3): Same mass, but the flat shell took 1.4 s and the pebble 0.4 s — 3.5 times as long (1). A flat particle meets more resistance from the water and rocks from side to side instead of falling straight (1). Clay particles are tiny flat discs, so they sink extremely slowly — the milky water took days to clear (1).
- Q10 (3): The smaller the grain, the longer it takes to settle — pebble 0.4 s, medium sand 5.8 s, clay several days (1). In moving water, fine grains stay suspended and are carried far; they settle only where water is calm for long enough — offshore, quiet bays, estuaries (1). Coarse grains drop out quickly, near their source, even in turbulent water (1).
- Q11 (5): Any five, in a sensible order: dry the sample completely so the grains do not stick (1); weigh it — the initial mass (1); pass it through a series of sieves, coarsest mesh first, each one finer, shaking each (1); weigh what each sieve catches, and what passes the finest (1); express each mass as a percentage of the initial mass (1); name each fraction by its Wentworth class, e.g. sand 1/16–2 mm (1).
- Q12 (4): Boulders · cobbles · pebbles · granules · very coarse sand · coarse sand · medium sand · fine sand · very fine sand · mud · silt and clay — all eleven in order (3; deduct 1 per error or omission). Boulders at least 256 mm; silt and clay less than 0.0039 mm (1).
Investigation 2 — an avalanche in a box
- Q13 (3): a: 20 ÷ (16.0 − 3.4) = 1.59 cm/s; b: 20 ÷ 9.1 = 2.20 cm/s; c: 20 ÷ 9.8 = 2.04 cm/s (1 each).
- Q14 (3): a and b: the steepness of the ramp (1). a and c: the amount of sediment in the slurry — its density (1). Controlled — any one: the same volume of slurry; the same soil; the same water depth; the same way of pouring; fresh clear water each run (1).
- Q15 (2): A steeper slope gives a faster current — 2.20 against 1.59 cm/s (1). More sediment, a denser slurry, gives a faster current — 2.04 against 1.59 cm/s (1).
- Q16 (2): Water carrying colour but no sediment simply mixed (1), so a turbidity current is driven by the extra density of the suspended sediment, which gravity pulls downslope — not by the pouring or the colour (1).
- Q17 (3): Each 5 cm took longer: 2.6, 2.9, 3.3, then 3.8 s (1). Any two reasons: sediment settles out, so the current becomes less dense; it mixes with the clear water above and is diluted; on the flat floor gravity no longer pulls it forward; friction with the floor (2).
- Q18 (5): A layer that thins away from the ramp (1); coarse at the bottom grading up to fine sand and mud on top (1); labels with thicknesses (1); named a graded bed (1); the coarse grains are heaviest and settle fastest, so they drop out of the slowing current first, and the finest last (1).
- Q19 (4): Ramp = the continental slope (1); slurry = the turbidity current — saturated sediment slumping from the shelf edge (1); flat floor = the abyssal plain (1); thick wedge at the foot = the continental rise (1).
- Q20 (4): Points plotted, including (0, 0) (1); axes labelled with units — time (h), distance (km) (1); sensible scales (1); a smooth curve that flattens (1).
- Q21 (4): 65 ÷ 0.98 = 66; 120 ÷ 2.07 = 58; 85 ÷ 1.85 = 46; 90 ÷ 2.70 = 33; 70 ÷ 2.70 = 26; 70 ÷ 2.98 = 23.5 km/h (3 for all six; 2 for four or five; 1 for two or three; accept ±1). Average: 500 ÷ 13.28 = 38 km/h (1).
- Q22 (3): Fastest at the start, about 66 km/h, then slowing steadily to about 23 km/h (1). Any two: the seabed flattens from the continental slope onto the abyssal plain; sediment settles out so the current becomes less dense; it spreads out and mixes with seawater; friction (2).
- Q23 (2): They broke at the same instant as the shock, so they were broken by the shaking and the slumping slope itself (1), not by a current travelling to them — there is no travel time to calculate a speed from (1).
- Q24 (4): Model: 2.20 cm/s = 0.022 m/s (1). Real: 66 km/h = 66 000 ÷ 3 600 = 18 m/s (1). About 800 times faster (1). Any one reason: the real current was hundreds of metres thick and carried well over a hundred cubic kilometres of sediment; it ran down a slope hundreds of kilometres long; it picked up more sediment as it eroded the seabed; the box water is only centimetres deep (1).
- Q25 (2): They were telegraph cables — the first transatlantic telephone cable was laid only in 1956 (1). It was not one line between London and New York: twelve cables linking North America and Europe were broken (1).
Investigation 3 — a Secchi tube
- Q26 (3): 8 g/L: 3.2 cm; 4 g/L: 6.3 cm; 2 g/L: 12.3 cm; 1 g/L: 25.0 cm (3 for all four; 2 for three; 1 for two).
- Q27 (4): Axes labelled with units (1); sensible scales (1); points accurate (1); a smooth curve that falls steeply, then levels off (1).
- Q28 (3): The more sediment, the shallower the disk disappears (1); each doubling of the concentration roughly halves the depth (1); depth × concentration ≈ 25 every time (25.6, 25.2, 24.6, 25.0) — the depth is inversely proportional to the concentration (1).
- Q29 (2): 25 ÷ 0.5 = about 50 cm (1). The bottle is only about 30 cm deep, so the disk could not disappear — the result is beyond the range of the apparatus, not "perfectly clear water" (1).
- Q30 (2): Repeats show whether readings agree, and a mean reduces the effect of one misjudged reading (1). The moment the disk "disappears" depends on the light and on the observer's eyes, so both must stay the same for a fair comparison (1).
- Q31 (3): Any two: phytoplankton (a bloom); dissolved brown colour from rivers; air bubbles or foam (2). In the kitchen test the water, the disk, the light and the observer stay the same and only the amount of sediment changes, so any change in depth is caused by the sediment (1).
- Q32 (4): Calm: 2.7 × 5.5 = 14.9 m (1). After the flood: 2.7 × 1.2 = 3.2 m (1). In the calm week 9 m lies inside the euphotic zone, so the seaweeds can photosynthesise (1); after the flood 9 m is far below it, so too little light reaches them (1).
- Q33 (3): Suspended sediment cuts the light — the Secchi depth falls as the concentration rises (1). The euphotic zone becomes shallower than the seaweed bed, so the seaweeds cannot make enough food (1). Over weeks they use up their stores and die, and the animals that feed and shelter in the bed go with them — the mud does not need to be poisonous to kill (1).
Investigation 4 — what mud does to living things
- Q34 (3): Clear: 22.6 − 20.0 = 2.6 °C (1). Muddy: 25.0 − 20.0 = 5.0 °C (1). Rates: about 0.87 and 1.67 °C per 10 min — the muddy jar warmed about twice as fast (1).
- Q35 (2): The suspended particles absorb the light instead of letting it pass through (1) and turn it into heat, which warms the water around them (1).
- Q36 (2): Any two: warmer water holds less dissolved oxygen; animals' metabolism speeds up so they need more oxygen; temperatures above an animal's tolerance stress or kill it; a warm surface layer stops mixing with the cold water below, so less oxygen reaches the bottom.
- Q37 (3): Clean water drained in the same time on every pour, 14–15 s (1). Muddy water drained more slowly every time, from 17 s to 72 s (1), because the particles are trapped in the filter's pores and build up into a layer that blocks the flow — the clogging accumulates (1).
- Q38 (4): (a) Particles lodge between the gill filaments and coat them in mud and mucus (1), so less water flows over the gills and less oxygen diffuses into the blood — gaseous exchange fails and the fish can suffocate; sharp grains also damage the thin gill surfaces (1). (b) A mussel pumps water through its gills to feed and to breathe (1); its gills clog with useless mud, so it spends energy clearing them or keeps its shell shut, getting less food and less oxygen — in heavy sediment it starves, suffocates or is buried (1).
- Q39 (1): Any one: water flows over a gill's surface rather than through pores; gills are living and make mucus to clear particles; a fish can swim away to clearer water; the filter exchanges no gases.
- Q40 (3): Photosynthesis releases oxygen (1), which collects in the air spaces inside the disc, so the disc becomes less dense than the water and floats (1). The control had no bicarbonate, so no carbon dioxide and no photosynthesis — and none floated, which shows the floating is caused by photosynthesis, not by the light or warmth alone (1).
- Q41 (5): Three lines on one set of axes (1); a key (1); axes labelled — time (min) and discs floating (1); sensible scales (1); accurate plotting (1).
- Q42 (3): Clear: about 8 min; 2 g/L: about 12 min; 8 g/L: not reached in 20 minutes (2 for all three; 1 for two). The muddier the water the light passes through, the slower the photosynthesis (1).
- Q43 (3): Independent: the amount of sediment in the screen jar — the light reaching the discs (1). Controlled — any two: the same number and size of discs; the same leaf; the same bicarbonate solution; the same lamp and distance; the same temperature; the same size of screen jar (2).
- Q44 (5): A paragraph; one mark each for any five: the water becomes turbid and the Secchi depth falls; less light reaches the reef, so seaweeds (and the algae in any corals) photosynthesise less; the euphotic zone may become shallower than the reef; suspended mud absorbs sunlight and warms the surface water, which then holds less oxygen; it clogs the gills of fish and the filters of mussels, sponges and other filter-feeders, which starve or suffocate; settling mud smothers and buries attached animals and seaweeds; over several weeks the harm spreads through the food web.
Investigation 5 — read a core
- Q45 (6): A column 24 cm tall (1); six layers at the right thicknesses — 4.2 cm, a thin line, 5.5 cm, 2.8 cm, 6.2 cm, 5.2 cm (2); each layer shaded differently, with layer 4 shown coarse at the base and fine at the top (1); a depth scale every 50 cm (1); each layer labelled (1).
- Q46 (4): Biogenous — layer 1 or 5, calcareous ooze of foraminifera shells (1). Lithogenous — layer 3 red clay, layer 2 volcanic ash, or the sand of layer 4 (1). Hydrogenous — the onion-ringed metal lumps in layer 6, manganese nodules precipitated from seawater (1). Cosmogenous — the tiny magnetic spheres in layer 6, from space dust (1).
- Q47 (4): Layer 4 (1). Any three: it is graded, coarse at the bottom and fine at the top; it has a sharp base that cuts into the layer below; it holds broken mussel and limpet shells, which live in shallow water, at 4 500 m — so the sediment came down from the shelf; it is coarse sand in the middle of fine deep-sea clay and ooze, which could never deliver grains that size (3).
- Q48 (4): Layer 4 (28 cm) was laid down in a few hours by one turbidity current, not over 28 000 years, so it is left out (1). 240 − 28 = 212 cm of slow sediment (1) × 1 000 years per cm = about 212 000 years (1). Explaining that 240 000 years would count the turbidite as slow sediment (1). (Leaving out the 1 cm ash layer as well — 211 000 years — is also correct.)
- Q49 (3): Its foraminifera live today only in cold polar water, so the sea here was much colder — an ice age (glacial period) (1). Top of layer 5: 126 − 28 = 98 cm ≈ 98 000 years; bottom: 188 − 28 = 160 cm ≈ 160 000 years (1). So roughly 100 000 to 160 000 years ago (1).
- Q50 (3): A dredge is dragged along the seabed and scoops up loose surface material (1). The layers are mixed and damaged, and exactly where each piece came from is not recorded (1). There would be no layer order and no depths, so nothing could be dated or interpreted; a corer brings the layers up in place, relative to each other (1).
- Q51 (3): (a) "Of or containing hydrogen" (1). (b) Here "hydro-" means water: hydrogenous sediment forms when dissolved minerals precipitate out of seawater; a manganese nodule is metal oxides with almost no hydrogen, so the definition points the wrong way (1). Better: sediment formed from minerals that precipitate directly out of seawater by chemical reactions (1).
- Q52 (3): It uses sound (sonar), not radar — radar uses radio waves, which hardly travel through seawater (1). Strong sound pulses are sent down; echoes return from the seabed and from each boundary between layers beneath it (1). Sound travels and reflects differently in sand, clay and rock, so the pattern of echoes shows the layers and what they are made of (1).
- Q53 (6): One mark per resource with a correct place, any six: sand and gravel for building (many countries); coal off Scotland; heavy-mineral sands (ilmenite, rutile, zircon) at Richards Bay; diamonds off Kleinzee and southern Namibia, washed from Kimberlite pipes by rivers as alluvial sediment; oil and gas off Angola; oil and gas off the Southern Cape (Mossel Bay); manganese nodules (with nickel, cobalt and copper) on the deep-ocean floor.
Marking note. Q48 is the question this sheet is built around: a learner who multiplies 240 by 1 000 has read the core as a clock that never stopped. Layer 4 is a whole graded bed laid down in an afternoon — the same deposit they made in a box in Investigation 2. In Q51, the booklet's definition is examinable, so a learner who writes it is not wrong in a definitions question; the mark in (b) is for seeing why it does not describe the sediment.